mahirjan يوللانغان ۋاقتى 2013-10-27 01:01:36

بىل (beal) پەرىزى ئانالىزى

ئۇستاز تاشپولات روزى بىل پەرىزى توغرىلىق يوللىغان تېمىسى مېنى ئۆزىگە مەپتۇن قىلىۋالدى، شۇڭا مەن پروگرامما ئارقىلىق بىل پەرزىنىڭ قانۇنىيىتىگە 10% يېقىنلاشتىم.

تۆۋەندىكىسى مەن ئېرىشكەن سانلىق مەلۇماتلار بولۇپ مۇلاھىزە قىلىپ باقسىڭىز كۈتۈلمىگەن نەتىجىگە ئېرىشىپ قېلىشىڭىز مۇمكىن.

تۆۋەندىكى سىتاتىسكىدا 2،3،4 لەرنىڭ بىل پەرىزىگە ئۇيغۇن كېلىدىغان دەرىجىلىرى كۆرسىتىلگەن.(ئۇچۇر مىقدارى زىيادە چوڭ بولغاچقا پەقەت 100 دەرىجىگىچە بولغان قىسىمىنى يوللاپ قويدۇم)



ئانالىز ئۇچۇرلىرىنى تۆۋەندىكى ئۇلىنىشتىن كۆرۈڭ، مۇنبەرگە يوللىسام قالايمىقان چىقىپ قالىدىكەن شۇڭا ئايرىم يوللىدىم.

http://218.84.79.165:82/beal.htm


kuyaxoghli يوللانغان ۋاقتى 2013-10-27 19:10:18

ئالدى بىلەن بېل پەرىزى توغرىلىق بىر چۈشەنچە بېرىۋەتسىڭىز بوپتىكەن ئەسلى.

kurax007 يوللانغان ۋاقتى 2013-10-27 20:17:58






سانلار نەزەرىيىسىدىكى بىل(Beal) پەرىزى



تاشپولات روزى




ئامېرىكالىق مىلياتىر ئەنجرو بىل (Andrew Beal) تۆۋەندىكى ماتېماتىكىلىق مەسىلىنى يەشسە 1 مىليون ئامېرىكا دوللىرى بېرىدىغانلىقىنى ئېلان قىلدى. ئەگەر بۇ پەرەزگە قىزىقسىڭىز ئىشلەپ بېقىڭ. بىل بۇ پەرەزنى 1993-يىلى ئوتتۇرىغا قويغان.



بىلپەرىزى:



ئەگەرA^x +B^y = C^z بولسا ئۇ ھالدا A, B, C لارنىڭ ئورتاق تۈپ سان كۆپەيتكۈچىلىرى بولىدۇ.



بۇ يەردە A, B, C لار مۇسبەت پۈتۈن سان ھەم x, y, z لار ئىككىدىن چوڭ بولغان مۇسبەت پۈتۈن سان. ^ بەلگىسى دەرىجىنى كۆرسىتىدۇ.



بىل پەرىزىنىڭ ئەنگىلىسچىسى.



Beal\"s conjecture is a conjecture in number theory:



If

      A^x +B^y = C^z,



where A, B, C, x, y, and z are positive integers with x, y, z > 2, then A, B, and C have a common prime factor.






    تىما ئادىرسى :          http://bbs.izdinix.com/forum.php?mod=viewthread&tid=55374



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mahirjan نىڭ ئانالىزى :



            (2x + 3^y = 4^z^بۇلغاندا


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2013-10-27 02:30:26.865--- x=58,y=2,z=29
2013-10-27 02:30:26.867--- x=58,y=3,z=29
2013-10-27 02:30:26.869--- x=60,y=2,z=30
2013-10-27 02:30:26.870--- x=60,y=3,z=30
2013-10-27 02:30:26.870--- x=60,y=4,z=30
2013-10-27 02:30:26.873--- x=62,y=2,z=31
2013-10-27 02:30:26.873--- x=62,y=3,z=31
2013-10-27 02:30:26.874--- x=62,y=4,z=31
2013-10-27 02:30:26.875--- x=62,y=5,z=31
2013-10-27 02:30:26.878--- x=64,y=2,z=32
2013-10-27 02:30:26.879--- x=64,y=3,z=32
2013-10-27 02:30:26.880--- x=64,y=4,z=32
2013-10-27 02:30:26.880--- x=64,y=5,z=32
2013-10-27 02:30:26.881--- x=64,y=6,z=32
2013-10-27 02:30:26.884--- x=66,y=2,z=33
2013-10-27 02:30:26.884--- x=66,y=3,z=33
2013-10-27 02:30:26.885--- x=66,y=4,z=33
2013-10-27 02:30:26.886--- x=66,y=5,z=33
2013-10-27 02:30:26.887--- x=66,y=6,z=33
2013-10-27 02:30:26.887--- x=66,y=7,z=33
2013-10-27 02:30:26.888--- x=66,y=8,z=33
2013-10-27 02:30:26.891--- x=68,y=2,z=34
2013-10-27 02:30:26.891--- x=68,y=3,z=34
2013-10-27 02:30:26.891--- x=68,y=4,z=34
2013-10-27 02:30:26.892--- x=68,y=5,z=34
2013-10-27 02:30:26.892--- x=68,y=6,z=34
2013-10-27 02:30:26.893--- x=68,y=7,z=34
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2013-10-27 02:30:26.896--- x=70,y=2,z=35
2013-10-27 02:30:26.897--- x=70,y=3,z=35
2013-10-27 02:30:26.897--- x=70,y=4,z=35
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2013-10-27 02:30:26.898--- x=70,y=6,z=35
2013-10-27 02:30:26.899--- x=70,y=7,z=35
2013-10-27 02:30:26.899--- x=70,y=8,z=35
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2013-10-27 02:30:26.900--- x=70,y=10,z=35
2013-10-27 02:30:26.902--- x=72,y=2,z=36
2013-10-27 02:30:26.903--- x=72,y=3,z=36
2013-10-27 02:30:26.903--- x=72,y=4,z=36
2013-10-27 02:30:26.904--- x=72,y=5,z=36
2013-10-27 02:30:26.904--- x=72,y=6,z=36
2013-10-27 02:30:26.904--- x=72,y=7,z=36
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2013-10-27 02:30:26.906--- x=72,y=11,z=36
2013-10-27 02:30:26.908--- x=74,y=2,z=37
2013-10-27 02:30:26.909--- x=74,y=3,z=37
2013-10-27 02:30:26.909--- x=74,y=4,z=37
2013-10-27 02:30:26.910--- x=74,y=5,z=37
2013-10-27 02:30:26.910--- x=74,y=6,z=37
2013-10-27 02:30:26.910--- x=74,y=7,z=37
2013-10-27 02:30:26.911--- x=74,y=8,z=37
2013-10-27 02:30:26.911--- x=74,y=9,z=37
2013-10-27 02:30:26.912--- x=74,y=10,z=37
2013-10-27 02:30:26.912--- x=74,y=11,z=37
2013-10-27 02:30:26.913--- x=74,y=12,z=37
2013-10-27 02:30:26.913--- x=74,y=13,z=37
2013-10-27 02:30:26.915--- x=76,y=2,z=38
2013-10-27 02:30:26.916--- x=76,y=3,z=38
2013-10-27 02:30:26.916--- x=76,y=4,z=38
2013-10-27 02:30:26.917--- x=76,y=5,z=38
2013-10-27 02:30:26.917--- x=76,y=6,z=38
2013-10-27 02:30:26.917--- x=76,y=7,z=38
2013-10-27 02:30:26.918--- x=76,y=8,z=38
2013-10-27 02:30:26.918--- x=76,y=9,z=38
2013-10-27 02:30:26.919--- x=76,y=10,z=38
2013-10-27 02:30:26.919--- x=76,y=11,z=38
2013-10-27 02:30:26.919--- x=76,y=12,z=38
2013-10-27 02:30:26.920--- x=76,y=13,z=38
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2013-10-27 02:30:26.922--- x=78,y=2,z=39
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2013-10-27 02:30:26.939--- x=80,y=2,z=40
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2013-10-27 02:30:26.948--- x=82,y=2,z=41
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2013-10-27 02:30:26.957--- x=84,y=2,z=42
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2013-10-27 02:30:26.967--- x=86,y=2,z=43
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2013-10-27 02:30:26.978--- x=88,y=2,z=44
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2013-10-27 02:30:26.987--- x=88,y=12,z=44
2013-10-27 02:30:26.988--- x=88,y=13,z=44
2013-10-27 02:30:26.989--- x=88,y=14,z=44
2013-10-27 02:30:26.990--- x=88,y=15,z=44
2013-10-27 02:30:26.990--- x=88,y=16,z=44
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2013-10-27 02:30:26.991--- x=88,y=18,z=44
2013-10-27 02:30:26.991--- x=88,y=19,z=44
2013-10-27 02:30:26.992--- x=88,y=20,z=44
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2013-10-27 02:30:26.995--- x=90,y=2,z=45
2013-10-27 02:30:27.008--- x=90,y=3,z=45
2013-10-27 02:30:27.008--- x=90,y=4,z=45
2013-10-27 02:30:27.009--- x=90,y=5,z=45
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2013-10-27 02:30:27.010--- x=90,y=8,z=45
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2013-10-27 02:30:27.020--- x=92,y=5,z=46
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2013-10-27 02:30:27.030--- x=94,y=2,z=47
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2013-10-27 02:30:27.043--- x=96,y=2,z=48
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2013-10-27 02:30:27.048--- x=96,y=12,z=48
2013-10-27 02:30:27.048--- x=96,y=13,z=48
2013-10-27 02:30:27.049--- x=96,y=14,z=48
2013-10-27 02:30:27.049--- x=96,y=15,z=48
2013-10-27 02:30:27.049--- x=96,y=16,z=48
2013-10-27 02:30:27.050--- x=96,y=17,z=48
2013-10-27 02:30:27.050--- x=96,y=18,z=48
2013-10-27 02:30:27.051--- x=96,y=19,z=48
2013-10-27 02:30:27.051--- x=96,y=20,z=48
2013-10-27 02:30:27.052--- x=96,y=21,z=48
2013-10-27 02:30:27.052--- x=96,y=22,z=48
2013-10-27 02:30:27.052--- x=96,y=23,z=48
2013-10-27 02:30:27.053--- x=96,y=24,z=48
2013-10-27 02:30:27.053--- x=96,y=25,z=48
2013-10-27 02:30:27.054--- x=96,y=26,z=48
2013-10-27 02:30:27.054--- x=96,y=27,z=48
2013-10-27 02:30:27.056--- x=98,y=2,z=49
2013-10-27 02:30:27.057--- x=98,y=3,z=49
2013-10-27 02:30:27.057--- x=98,y=4,z=49
2013-10-27 02:30:27.057--- x=98,y=5,z=49
2013-10-27 02:30:27.058--- x=98,y=6,z=49
2013-10-27 02:30:27.058--- x=98,y=7,z=49
2013-10-27 02:30:27.059--- x=98,y=8,z=49
2013-10-27 02:30:27.059--- x=98,y=9,z=49
2013-10-27 02:30:27.060--- x=98,y=10,z=49
2013-10-27 02:30:27.060--- x=98,y=11,z=49
2013-10-27 02:30:27.061--- x=98,y=12,z=49
2013-10-27 02:30:27.061--- x=98,y=13,z=49
2013-10-27 02:30:27.061--- x=98,y=14,z=49
2013-10-27 02:30:27.062--- x=98,y=15,z=49
2013-10-27 02:30:27.062--- x=98,y=16,z=49
2013-10-27 02:30:27.063--- x=98,y=17,z=49
2013-10-27 02:30:27.063--- x=98,y=18,z=49
2013-10-27 02:30:27.063--- x=98,y=19,z=49
2013-10-27 02:30:27.072--- x=98,y=20,z=49
2013-10-27 02:30:27.072--- x=98,y=21,z=49
2013-10-27 02:30:27.073--- x=98,y=22,z=49
2013-10-27 02:30:27.073--- x=98,y=23,z=49
2013-10-27 02:30:27.074--- x=98,y=24,z=49
2013-10-27 02:30:27.074--- x=98,y=25,z=49
2013-10-27 02:30:27.075--- x=98,y=26,z=49
2013-10-27 02:30:27.075--- x=98,y=27,z=49
2013-10-27 02:30:27.075--- x=98,y=28,z=49







kurax007 يوللانغان ۋاقتى 2013-10-27 20:29:40



سىزA,B,C نى 4، 3،2دەپ ئاپسىزئۇ پەرەزدە دىيىلدۇكى :ئەگەر A^x +B^y = C^z بولسا ئۇ ھالدا A, B, C لارنىڭ ئورتاق تۈپ سان كۆپەيتكۈچىلىرى بولىدۇ.



سىز ئالغان A,B,C نىڭ قىممىتى 4، 3،2 لەرنىڭ ئۇرتاق كۆپەيىتكۈچىسى پەقەت ۋە پەقەت 1، ئورتاق تۈپ سان كۆپەيتكۈچىسى يوق(1 تۈپ سان ئەمەس).



   شۇڭا A,B,C نىڭ قىممىتى 4، 3،2 دەپ ئېلىشىڭىز مىنىڭچە توغرا ئەمەس ، باشقا توپ سان كۆپەيىتكۈچىسى بار بولغان سانلارنى قۇيۇپ سىناپ بېقىڭ .

TashpolatRozi يوللانغان ۋاقتى 2013-10-28 04:58:28

3- قەۋەتتىكى kurax007نىڭ يازمىسىدىن نەقىل



سىز A,B,C نى 4، 3، 2 دەپ ئاپسىز ئۇ پەرەزدە دىيىلدۇكى : ئەگەر A^x +B^y = C^z بولسا ئۇ ھالدا A, B, C لارنىڭ ئورتاق تۈپ سان كۆپەيتكۈچىلىرى بولىدۇ.



سىز ئالغان A,B,C نىڭ قىممىتى 4، 3، 2 لەرنىڭ ئۇرتاق كۆپەيىتكۈچىسى پەقەت ۋە پەقەت 1 ، ئورتاق تۈپ سان كۆپەيتكۈچىسى يوق(1 تۈپ سان ئەمەس) .




شۇڭا A,B,C نىڭ قىممىتى 4، 3، 2 دەپ ئېلىشىڭىز مىنىڭچە توغرا ئەمەس ، باشقا توپ سان كۆپەيىتكۈچىسى بار بولغان سانلارنى قۇيۇپ سىناپ بېقىڭ .




سىز مەسىلىنى 100% چۈشىنىپسىز. تەھلىلىڭىز توپ توغرا.




kurax007 يوللانغان ۋاقتى 2013-10-28 11:52:35

تاشپۇلات مۇئەللىمنىڭ مۇئەييەنلەشتۈگىنىگە رەخمەت (خۇشال بولغان چىراي ئىپادىسى )



   قارىسام بۇمەسلىنى تۇلۇق كۇرىستا ئۆگەنگەن ماتىماتكا بىلەن يېقىن كەگىلى بۇلىدىغاندەك ئەمەس .

mahirjan يوللانغان ۋاقتى 2013-10-28 20:03:31

خاتالىقنى كۆرسىتىپ بەرگىنىڭلارغا كۆپ رەھمەت ... شۇتاپتا مۇشۇنىڭ ئۆزىنىڭمۇ قانۇنىيىتى تاپماقمۇ بەك تەس ئىكەن... مۇمكىن بولسا ماڭا A B C نىڭ قىممىتىنى بېرىڭلار ، دەرىجىلىرىنى ھېسابلاپ تېپىپ باقاي.

kurax007 يوللانغان ۋاقتى 2013-10-28 20:32:17

A, B, C نىڭ قىممىتىنى 6 ، 4 ، 2 دەپ ئېلىپ ئىشلەپ بېقىڭە ، ئۇلارنىڭ ئورتاق تۈپ سان كۇپەيىتكۈچىسى 2 .



يەنە مەسلەن : A, B, C نىڭ ئورنىغا قۇيۇشقا بولىدىغان سانلار :





   15 ، 10 ، 5ئورتاق تۈپ سان كۇپەيىتكۈچىسى5 .

   9 ، 6 ، 3ئورتاق تۈپ سان كۇپەيىتكۈچىسى3

   49 ، 21 ، 14 ئورتاق تۈپ سان كۇپەيىتكۈچىسى 7 .

   ........
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